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2025-11-26 17:34:58 +08:00
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@@ -70,14 +70,16 @@ Let $M$ be a binary matroid with binary representation $B\in \F_2^{n\times m}$.
\end{lemma}
\begin{proof}
Let $M'$ be $M\left(\begin{bmatrix}B\\ \sigma\end{bmatrix}\right)$ and let the ground set be $E$.
$\lambda(M')\leq \lambda(M)$ (row space).
Let $F^*\in \argmin_{F\subset E} \frac{|E-F|}{r'(E)-r'(F)}$.
We have $\lambda(M')\leq \lambda(M)$ since the row space becomes larger.
Let $F^*\in \argmin_{F\subset E} \frac{|E-F|}{r'(E)-r'(F)}$. Let $r$ be the rank of $M$ and let $r'$ be the rank of $M'$.
We can assume that $r(E)-r(F^*)\geq 1$ since otherwise we have $r'(E)-r'(F^*)\leq 1$ which implies the gap of $M'$ is 1.
\begin{equation*}
\begin{aligned}
\sigma(M') &= \frac{|E-F^*|}{r'(E)-r'(F^*)}\\
&\geq \frac{|E-F^*|}{r(E)+1-r(F^*)}\\
&\geq \frac{|E-F^*|}{2(r(E)-r(F^*)}\\
&\geq \frac{|E-F^*|}{2(r(E)-r(F^*))}\\
&\geq \frac{\sigma(M)}{2}
\end{aligned}
\end{equation*}