@@ -70,14 +70,16 @@ Let $M$ be a binary matroid with binary representation $B\in \F_2^{n\times m}$.
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\end{lemma}
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\begin{proof}
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Let $M'$ be $M\left(\begin{bmatrix}B\\ \sigma\end{bmatrix}\right)$ and let the ground set be $E$.
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$\lambda(M')\leq \lambda(M)$ (row space).
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Let $F^*\in \argmin_{F\subset E} \frac{|E-F|}{r'(E)-r'(F)}$.
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We have $\lambda(M')\leq \lambda(M)$ since the row space becomes larger.
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Let $F^*\in \argmin_{F\subset E} \frac{|E-F|}{r'(E)-r'(F)}$. Let $r$ be the rank of $M$ and let $r'$ be the rank of $M'$.
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We can assume that $r(E)-r(F^*)\geq 1$ since otherwise we have $r'(E)-r'(F^*)\leq 1$ which implies the gap of $M'$ is 1.
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\begin{equation*}
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\begin{aligned}
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\sigma(M') &= \frac{|E-F^*|}{r'(E)-r'(F^*)}\\
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&\geq \frac{|E-F^*|}{r(E)+1-r(F^*)}\\
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&\geq \frac{|E-F^*|}{2(r(E)-r(F^*)}\\
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&\geq \frac{|E-F^*|}{2(r(E)-r(F^*))}\\
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&\geq \frac{\sigma(M)}{2}
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\end{aligned}
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\end{equation*}
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