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main.tex
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main.tex
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\documentclass[12pt]{article}
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\documentclass[a4paper,11pt]{article}
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\usepackage{chao}
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\usepackage{algo}
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\geometry{a4paper,margin=2cm}
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% \usepackage[breakable, theorems, skins]{tcolorbox}
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% \tcbset{enhanced}
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% \DeclareRobustCommand{\note}[2][blue]{%
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% \begin{tcolorbox}[
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% breakable,
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% left=0pt,
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% right=0pt,
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% top=0pt,
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% bottom=0pt,
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% colback=white,
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% colframe=#1,
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% width=\dimexpr\textwidth\relax,
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% enlarge left by=0mm,
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% boxsep=5pt,
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% arc=0pt,outer arc=0pt,
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% ]
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% #2
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% \end{tcolorbox}
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% }
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\geometry{margin=2cm}
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\title{Connectivity Interdiction Notes}
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\title{Faster FPTAS for Connectivity Interdiction}
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\author{}
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\date{}
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@@ -40,7 +21,7 @@
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Note that $\mathcal F$ is usually not explicitly given.
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\begin{problem}[Normalized knapsack]\label{nknap}
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Given the same input as \autoref{bfreeknap}, find $\min \limits_{X\in \mathcal F, F\subset E} \frac{w(X\setminus F)}{B-c(F)}$ such that $c(F)\leq b$.
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Given the same input as \autoref{bfreeknap}, find $\min \limits_{X\in \mathcal F, F\subset E} \frac{w(X\setminus F)}{B-c(F)}\; s.t.\; c(F)\leq b$.
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\end{problem}
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In \cite{vygen_fptas_2024} the normalized min-cut problem use $B=b+1$. Here we use any integer $B>b$ and see how their method works.
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@@ -364,8 +345,11 @@ It follows directly from the preceding lemma that $\lambda^*$ can be computed in
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Reweighting the graph takes linear time.
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Finding $<2$-approx mincut takes $\tilde O(n^3)$.
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An $1+\e$ approximate solution to knapsack can be found in time $\tilde O(m+\frac{1}{\e^2})$ \cite{10.1145/3618260.3649730}.
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The total complexity is $\tilde O(mn^3+\frac{n^3}{\e^2})$.
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The total complexity is $\tilde O(m^2+n^3 T)$, where $T$ is the running time of FPTAS for 0-1 knapsack.\footnote{An $1+\e$ approximate solution to knapsack can be found in time $\tilde O(m+\frac{1}{\e^2})$ \cite{10.1145/3618260.3649730}.}
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\subsection{Avoid the parametric search}
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The $m^2$ term in the complexity is hard to improve.
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So we consider using binary search to find an $(1+\e)$-approximate $\lambda^*$.
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\bibliographystyle{plain}
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\bibliography{ref}
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Reference in New Issue
Block a user