diff --git a/main.tex b/main.tex index ac24151..7254219 100644 --- a/main.tex +++ b/main.tex @@ -46,13 +46,13 @@ \begin{problem}[connectivity interdiction {[Zenklusen, ORL'14]}] Let $G=(V,E)$ be a graph with edge weights $w:E\to\Z_+$ and edge removal costs $c:E\to\Z_+$ and let $B\in \mathbb Z_+$ be the budget. -Find $F\subset E$ with $w(F)\leq B$ s.t. the min-cut in $G-F$ is minimized. +Find $F\subset E$ with $c(F)\leq B$ s.t. the edge connectivity in $G-F$ is minimized. \end{problem} \p \begin{problem}[$B$-free min-cut] Given the same input, define weight function for cuts -\[ w'(\delta(X))=\min_{F\subset \delta(X),c(F)\leq B} w(\delta(X)-F)\] +\[ w'(\delta(X))=\min_{\substack{F\subset \delta(X)\\ c(F)\leq B}} w(\delta(X)-F)\] Find the cut with minimum weight $w'$. \end{problem} @@ -68,22 +68,25 @@ Find the cut with minimum weight $w'$. \end{frame} \begin{frame}{Previous works} +\newcommand{\blueT}{\textcolor{blue}{T}} \begin{table}[h] \centering \begin{tabular}{c c c c} \toprule -unit cost $w(\cdot)=1$ & general case & random? & ref \\ +Unit cost $\textcolor{gray}{c(\cdot)=1}$ & General case & Random? & Reference \\ \midrule $O(m^2n^4\log n)$ & $O(m^{2+1/\e}n^4\log n)$ & $\times$ & [Zenklusen, ORL'14] \\ +$\tilde O(m+n^4 B)$ & $O(n^4\log(Bnw_{\max})\blueT)$ & $\times$ & [Huang \etal{}, IPCO'24]\\ +$\tilde O(m^2+n^3B)$ & $\tilde O(m^2+n^3\blueT)$ & $\times$ & this work\\ +\midrule $O(mn^4\log^2 n)$ & $O(m^{1+1/\e}n^4\log^2 n)$ & $\checkmark$ & [Zenklusen, ORL'14] \\ -$\tilde O(m+n^4 B)$ & $O(\frac{m^2n^4}{\e}\log(Bnw_{\max}))$ & $\times$ & [Huang \etal{}, IPCO'24]\\ -$\tilde O(mn^3\log w_{\max})$ & - & $\checkmark$ & [Drange \etal{}, AAAI'26]\\ -$\tilde O(m^2+n^3B)$ & $\tilde O(m^2+mn^3+n^3/\e)$ & $\times$ & this work\\ -$\tilde O(m+n^3B)$ & $\tilde O(mn^3+n^3/\e)$ & $\checkmark$ & this work\\ +$\tilde O(mn^3\log w_{\max})$ & & $\checkmark$ & [Drange \etal{}, AAAI'26]\\ +$\tilde O(m+n^3B)$ & $\tilde O(m+n^3\blueT)$ & $\checkmark$ & this work\\ \bottomrule \end{tabular} \caption{PTASes for connectivity interdiction} \end{table} +$\blueT$ is the complexity of FPTAS for 0-1 knapsack. \end{frame} \begin{frame}{Method in [Huang \etal{}, IPCO'24]}