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Yu Cong
2026-01-06 14:47:26 +08:00
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@@ -217,7 +217,7 @@ Consider $L(\lambda)$ for cut problem. One can see that the optimal $\lambda$ is
\subsection{integrality gap}
I guess the 2-approximate min-cut enumeration algorithm implies an integrality gap of 2 for cut interdiction problem. \textcolor{red}{Which is wrong}.
% I guess the 2-approximate min-cut enumeration algorithm implies an integrality gap of 2 for cut interdiction problem. \textcolor{red}{Which is wrong}.
First consider the dual of linear relaxation of \autoref{ip:interdiction}.