\frame[plain]{\titlepage} \frame{\frametitle{Outline}\tableofcontents} \section{Introduction} \begin{frame} \frametitle{Latex and Beamer} LaTeX is a high-quality typesetting system; it includes features designed for the production of technical and scientific documentation. \vspace{0.4cm} \pause Beamer is a LaTeX class to create powerful, flexible and nice-looking presentations and slides. The beamer class is focussed on producing (on-screen) presentations, along with support material such as handouts and speaker notes. \end{frame} \section{Beamer Basic} \subsection{Hightlight} \begin{frame} \frametitle{Block and Alert} \begin{block}{Pythagorean theorem} \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0.6pt} $$a^2 + b^2 = c^2$$ % \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0.1pt} where c represents the length of the hypotenuse and a and b the lengths of the triangle's other two sides. \end{block} \begin{alertblock}{Remark} \begin{itemize} \item the environment above is \alert{block} \item the environment here is \alert{alertblock} \end{itemize} \end{alertblock} \end{frame} \begin{frame} \frametitle{Proof} \begin{block}{Pythagorean theorem} \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0.1pt} $$a^2 + b^2 = c^2$$ % \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0.2pt} \end{block} \vspace{0.4cm} \begin{proof} \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0pt} \begin{align*} &3^2 + 4^2 = 5^2\\ &5^2 + 12^2 = 13^2 \end{align*} % \vspace*{-\baselineskip}\setlength\belowdisplayshortskip{0pt} \end{proof} \end{frame} \subsection{Other Environments} \begin{frame}{Algorithm} \scriptsize \begin{algorithm}[H] \KwData{this text} \KwResult{how to write algorithm with \LaTeX2e } initialization\; \While{not at end of this document}{ read current\; \eIf{understand}{ go to next section\; current section becomes this one\; }{ go back to the beginning of current section\; } } \caption{How to write algorithms (copied from \href{https://en.wikibooks.org/wiki/LaTeX/Algorithms}{here})} \end{algorithm} \end{frame} \begin{frame}[fragile] \frametitle{An Algorithm For Finding Primes Numbers.} \scriptsize \begin{verbatim} int main (void) { std::vector is_prime (100, true); for (int i = 2; i < 100; i++) if (is_prime[i]) { std::cout << i << " "; for (int j = i; j < 100; is_prime [j] = false, j+=i); } return 0; } \end{verbatim} \vspace{-0.7cm} \begin{uncoverenv} Note the use of \verb|\alert|. \end{uncoverenv} \end{frame} \begin{frame}{More} More environments such as \begin{itemize} \item Definition \item lemma \item corollary \item example \end{itemize} \end{frame} \section{Beamer More} \subsection{Split Screen} \begin{frame}{Minipage} \begin{minipage}{0.5\linewidth} \begin{figure}[h] \includegraphics[width=\textwidth]{imgs/pythagorean.jpg} \end{figure} \end{minipage}% \hfill \begin{minipage}{0.4\linewidth} \begin{enumerate} \item item \item another \item more \begin{itemize} \item first \item second \item third \end{itemize} \end{enumerate} \end{minipage} \end{frame} \begin{frame}{Columns} \begin{columns} \column{0.5\textwidth} This is a text in first column. $$E=mc^2$$ \begin{itemize} \item First item \item Second item \end{itemize} \column{0.5\textwidth} \begin{block}{first block} columns achieves splitting the screen \end{block} \begin{block}{second block} stack block in columns \end{block} \end{columns} \end{frame} \subsection{Table} \begin{frame}{Create Tables} \begin{center} \begin{table}[!t] % \caption{Three line} % \label{table_time} \begin{tabular}{ccc} \toprule first&second&third\\ \midrule 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \\ \bottomrule \end{tabular} \end{table} \end{center} \end{frame} \subsection{Math} \begin{frame}{Equation1} A matrix in text must be set smaller: $\bigl(\begin{smallmatrix} a&b \\ c&d \end{smallmatrix} \bigr)$ to not increase leading in a portion of text. \[ f(n) = \begin{cases} n/2 & \quad \text{if } n \text{ is even}\\ -(n+1)/2 & \quad \text{if } n \text{ is odd} \end{cases} \] $$50 apples \times 100 apples = lots of apples^2$$ \end{frame} \begin{frame}{Equation2} $$\sum_{\substack{04\right)$$ $$( a ), [ b ], \{ c \}, | d |, \| e \|, \langle f \rangle, \lfloor g \rfloor, \lceil h \rceil, \ulcorner i \urcorner$$ \end{frame} \begin{frame}{Equation3} $$Q(\alpha)=\alpha_i\alpha_jy_iy_j(x_i\cdot x_j)$$ $$Q(\alpha)=\alpha^i\alpha^jy^{(i)}y^{(j)}(x^i\cdot x^j)$$ $$\Gamma=\beta+\alpha+\gamma+\rho$$ \end{frame} \section{Conclusion} \begin{frame}{End} The last page. \end{frame}